Euler Wrote:
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> suppose 'x' is the equivalent to half it's
> integer. you can take the prime of that number,
> and it's divisible by the total number of digits.
> same as explained above except in reverse. prime
> numbers are special in that way. you can
> calculate their sums in respect to their value
> divided by half.
I'm getting the feeling that you're full of shit... x equals half its (whatever "it" is) integer?
So you're saying x=x/2 ?? HUH!?
Then take the "prime" of that number? How do you take a prime of a given number?
Then you're saying that the prime is divisible by the total number of digits? I thought primes weren't divisible by anything but themselves (and 1)?
Calculate their sums "in respect" to their value divided in half? HUH!?
Let's take 7 for example... 7 is a prime... you're saying that seven is equal to 3.5?
Signatures are for fags