4CKUM Wrote:
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> This is a little tricky to answer. The short
> answer, if the gauge of the wire is the same in
> both cases, then the 1000' feet of wire will
> provide additional resistance and therefore flow
> less current. It would drain the battery slower.
>
> Think about the extreme case, say at 1000 ohm
> resistor across the battery instead of your 1000'
> of wire and bulb. The 1000 ohm resistor would
> draw less current. Of even more extreme, air
> across the terminals -- in the megaohms. How
> quickly does a battery discharge just sitting
> there?
>
> The "right" answer is that the battery is a
> voltage source. Since it isn't an ideal voltage
> source you would model it as an an ideal voltage
> source in series with some internal resistance.
> The internal resistance of a lead acid battery
> (12V) is probably fairly low compared to your load
> so just approximate it as 0.
>
> If instead you had an ideal current source, it
> would drive the specified current across the given
> load. Adding more wire would cause the voltage
> across the wire and bulb to increase so that the
> current across is the same.
Blessed are the murderous.
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